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} - returnans; the } the the intMain ()94 { the while(SCANF ("%d%d", n,m)! =EOF) the { the if(!n !m) Break;98memset (head,-1,sizeof(head)); Aboutedgenum=0; - Charstr[111][111];101memset (str,0,sizeof(str));102 for(intI=1; i)103 {104scanf"%s", str[i]+1); the }106 from=n*m+1;107to= from+1;108 inth[111],c[111],cnt=0;109 inth2[111],c2[111],cnt2=0; the for(intI=1; i)111 { the for(intj=1;

; Support before and after, Taobao support "large down jacket" a word: 12.23 days, "large down jacket" The expression index is only 2.19 million; 12.24 days, after the support of Taobao home page, "a large down jacket" the expression of the exponential increase to 34 million; 12.25 days, the term "large down jacket" reached its peak, showing the index reached 40 million; Support period, "large down jacket" The word click Rate, click Conversion ra

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, y;} A[n],b[n];inlineintDis (data a,data b) {returnABS (a.x-b.x) +abs (a.y-b.y);}structedge{intV,ne,c,f,w;} E[m1];intCnt,h[n];inlinevoidInsintUintVintCintW) {CNT++; E[CNT].V=v;e[cnt].c=c;e[cnt].f=0; e[cnt].w=W; E[cnt].ne=h[u];h[u]=CNT; CNT++; E[CNT].V=u;e[cnt].c=0; e[cnt].f=0; e[cnt].w=-W; E[cnt].ne=h[v];h[v]=CNT;}voidbuild () {CNT=0; memset (H,0,sizeof(h)); S=0; t=n1+n2+1; for(intI=1; i) for(intj=1; j1, Dis (a[i],b[j])); for(intI=1; i1,0); for(intI=1; i1,0);}intD[n],q[n],head,tail,i

case starts with a line giving two integers n and m, where N is the number of rows of the map, and m is the number of columns. the rest of the input will be n lines describing the map. you may assume both N and m are between 2 and 100, aggressive. there will be the same number of 'H's and 'M' s on the map; and there will be at most 100 houses. input will terminate with 0 0 for N and M. Output For each test case, output one line with the single integer, which is the minimum amount, in dollars,

/* Question: Given a n * m map, there are several man and house on the map, and the number of man and house are consistent. $1 (unit cost = unit distance) is required for a man to move one cell. Only one man can be accommodated in one house. Now all man is required to stay in the house and the minimum fee is required. The minimum cost of the maximum flow to the spfa to find the minimum

with a line giving-integers n and m, where N is the number of rows of the map, and M are the number of Columns. The rest of the input would be N lines describing the map. Assume both N and M are between 2 and inclusive. There would be the same number of ' H ' s and ' M's on the map; And there'll is at the most houses. Input would terminate with 0 0 for N and M.Outputfor each test case, output one line with the single integer, which are the minimum amount, in dollars, your need to PA Y.Sample In